document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1108356>Question 1108356</A>: <I><SPAN STYLE=\"word-break: break-all;\">  If 63 equal to 6 times a certain number, increased by 15, find the number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #723361 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=723361\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let's write the equation exactly the way the problem says, I'll call the \"certain number\" x:<BR>\n" );
document.write( "63 = 6x + 15 subtract 15 from both sides<BR>\n" );
document.write( "48 = 6x flip the equation so we have the unknown on the left:<BR>\n" );
document.write( "6x = 48 divide both sides by 6:<BR>\n" );
document.write( "x = 8 </SPAN>\n" );
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