document.write( "Question 1108303: To prepare for a marathon run, Sue ran
\n" );
document.write( "56
\n" );
document.write( "56 miles before she blistered her heel, and then she walked
\n" );
document.write( "1
\n" );
document.write( "1 additional mile. Her running speed was
\n" );
document.write( "16
\n" );
document.write( "16 times as fast as her walking speed. She was running and walking for
\n" );
document.write( "9
\n" );
document.write( "9 hours. Find Sue's running speed. \n" );
document.write( "
Algebra.Com's Answer #723348 by Alan3354(69443) You can put this solution on YOUR website! To prepare for a marathon run, Sue ran 56 miles before she blistered her heel, and then she walked 1 additional mile. Her running speed was 16 times as fast as her walking speed. She was running and walking for 9 hours. Find Sue's running speed. \n" ); document.write( "-------------- \n" ); document.write( "56/R + 1/W = 9 \n" ); document.write( "R = 16W \n" ); document.write( "56/16W + 1/W = 9 \n" ); document.write( "56 + 16 = 144W \n" ); document.write( "W = 1/2 mi/hr \n" ); document.write( "R = 8 mi/hr \n" ); document.write( " |