document.write( "Question 1108310: solve for
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document.write( "                                   ^\r\n" );
document.write( "                                 / |\\r\n" );
document.write( "                                /  | \\r\n" );
document.write( "                              6/   |  \4\r\n" );
document.write( "                              /    |   \\r\n" );
document.write( "                             /     |    \\r\n" );
document.write( "                            /___x__|_____\\r\n" );
document.write( "                            |-----6-------|
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Algebra.Com's Answer #723337 by greenestamps(13215)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "The triangle is isosceles, with two sides of length 6. Then using the side with length 4 as the base, the height of the triangle will be the length of the other leg of a right triangle with one leg 2 (half of the 4) and hypotenuse 6. So the height is
\n" ); document.write( "\"sqrt%286%5E2-2%5E2%29+=+sqrt%2836-4%29+=+sqrt%2832%29+=+4%2Asqrt%282%29\"

\n" ); document.write( "Then the area of the triangle is one-half base times height: \"2%284%2Asqrt%282%29%29+=+8%2Asqrt%282%29\"

\n" ); document.write( "Then, using your diagram with 6 as the base, the area of the triangle is one-half base times the altitude you show (call it h):
\n" ); document.write( "\"8%2Asqrt%282%29+=+3h\"
\n" ); document.write( "\"h+=+8%2Asqrt%282%29%2F3\"

\n" ); document.write( "And then the unknown x we are looking for is the other leg of a right triangle with one leg h and hypotenuse 6:
\n" ); document.write( "\"x%5E2%2B%288%2Asqrt%282%29%2F3%29%5E2+=+6%5E2\"
\n" ); document.write( "\"x%5E2%2B128%2F9+=+36+=+324%2F9\"
\n" ); document.write( "\"x%5E2+=+196%2F9\"
\n" ); document.write( "\"x+=+14%2F3\" \n" ); document.write( "
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