document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1108319>Question 1108319</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the first three terms in an arithmetic progression are (x+3), (3x-10) and (2x+10), find x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #723332 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=723332\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The difference between adjacent terms is the same<BR>\n" );
document.write( "3x-10-(x+3)=2x-13<BR>\n" );
document.write( "2x+10-(3x-10)=-x+20<BR>\n" );
document.write( "Therefore, 2x-13=-x+20<BR>\n" );
document.write( "3x=33<BR>\n" );
document.write( "x=11 ANSWER<BR>\n" );
document.write( "the terms are 14, 23, and 32, which is an arithmetic progression. </SPAN>\n" );
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