document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1108275>Question 1108275</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello! I don't understand these two questions, if its possible, please help me solve this step by step asap, thank you sooo much, the link leads to the two questions<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #723305 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=723305\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> first diagram:\r<BR>\n" );
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document.write( "angle AEB = DEC because vertical angles are equal.\r<BR>\n" );
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document.write( "side AE = side EC because line segment AEC bisected by line segment BED.\r<BR>\n" );
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document.write( "side BE =side ED because line segment BED bisected by line segment AEC.\r<BR>\n" );
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document.write( "triangles ABE congruent to triangle CDE by SAS postulate.\r<BR>\n" );
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document.write( "side AE congruent to side EC<BR>\n" );
document.write( "side BE congruent to side ED<BR>\n" );
document.write( "angle AEB congruent to angle CED\r<BR>\n" );
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document.write( "two triangle are congruent if the corresponding sides and the included angle between them are congruent.\r<BR>\n" );
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document.write( "your solution is triangle ABE congruent to triangle CDE by SAS.\r<BR>\n" );
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document.write( "second diagram:\r<BR>\n" );
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document.write( "the sum of the remote interior angles is equal to the exterior angle.\r<BR>\n" );
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document.write( "this means that angle A + angle B = angle BCD.\r<BR>\n" );
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document.write( "you should get:\r<BR>\n" );
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document.write( "5x-135 + 5x-155 = 6x - 122.\r<BR>\n" );
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document.write( "combine like terms to get 10x - 290 = 6x - 122\r<BR>\n" );
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document.write( "subtract 6x from both sides of this equation and add 290 to both sides of this equation to get 10x - 6x = 290 - 122.\r<BR>\n" );
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document.write( "combine like terms to get 4x = 168\r<BR>\n" );
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document.write( "divide both sides of this equation by 4 to get x = 42\r<BR>\n" );
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document.write( "when x = 42, you get:\r<BR>\n" );
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document.write( "angle B = 5x - 135 = 75<BR>\n" );
document.write( "angle A = 5x - 155 = 55<BR>\n" );
document.write( "angle BCD = 6x - 22 = 130\r<BR>\n" );
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document.write( "angle BCA is supplemental to angle BCD, therefore angle BCA is equal to 180 - 130 = 50\r<BR>\n" );
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document.write( "you get:\r<BR>\n" );
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document.write( "angle B = 75<BR>\n" );
document.write( "angle A = 55<BR>\n" );
document.write( "angle C = 50\r<BR>\n" );
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document.write( "angle C is the same as angle BCA.   \r<BR>\n" );
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document.write( "sum of the angles of a triangle is equal to 180.<BR>\n" );
document.write( "75 + 55 + 50 = 180<BR>\n" );
document.write( "this part checks out.\r<BR>\n" );
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document.write( "sum of the remote interior angles is equal to the exterior angle.<BR>\n" );
document.write( "angle A plus angle B = 130<BR>\n" );
document.write( "angle BCD = 130<BR>\n" );
document.write( "this part checks out.\r<BR>\n" );
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document.write( "your solution is that angle BCA is equal to 50 degrees.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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