document.write( "Question 99387: Could someone please help me. So far I am doing well on my assignment with what I have learned from all of your help, it is these word problems that are tripping me up.\r
\n" ); document.write( "\n" ); document.write( "Lee can ride his bicycle 50 mi in the same time it takes him to drive 125 mi. If his driving rate is 30 mi/h faster than his rate bicycling, find each rate
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Algebra.Com's Answer #72328 by ankor@dixie-net.com(22740)\"\" \"About 
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Lee can ride his bicycle 50 mi in the same time it takes him to drive 125 mi. If his driving rate is 30 mi/h faster than his rate bicycling, find each rate
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\n" ); document.write( "Recognize the fact that the bicycle trip time = the car trip time
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\n" ); document.write( "Let s = speed of the bicycle
\n" ); document.write( "Then
\n" ); document.write( "(s+30) = speed of the car
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\n" ); document.write( "Write a time equation: Time = dist/speed
\n" ); document.write( " Bike time = Car time
\n" ); document.write( "\"50%2Fs\" = \"125%2F%28%28s%2B30%29%29\"
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\n" ); document.write( "Cross multiply
\n" ); document.write( "125s = 50(s+30)
\n" ); document.write( "125s = 50s + 1500
\n" ); document.write( "125s - 50s = 1500
\n" ); document.write( "75s = 1500
\n" ); document.write( "s = 1500/75
\n" ); document.write( "s = 20 mph is speed of the bicycle
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\n" ); document.write( "20 + 30 = 50 mph is car's speed
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\n" ); document.write( "Check solution by finding the time:
\n" ); document.write( "50/20 = 2.5 hrs
\n" ); document.write( "125/50 = 2.5 hrs, also
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