document.write( "Question 1108137: What is the % w/v of 8g of dextrose in 50ml? \n" ); document.write( "
Algebra.Com's Answer #723239 by KMST(5328)\"\" \"About 
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If you work in a life sciences lab, you find concentrations listed as %w/v sometimes.
\n" ); document.write( "For %w/v, we use grams an milliliters as if they were the same unit.
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\n" ); document.write( "If the total volume of the solution is 50mL,
\n" ); document.write( "then the % w/v is \"8%2F50=16%2F100=highlight%28%2216%25%22%29\" .
\n" ); document.write( "That is where a math problem ends.
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\n" ); document.write( "\n" ); document.write( "That solution will NOT weigh 58 g, so its %w/w would NOT be
\n" ); document.write( "\"8g%2F%2258+g%22=approximately+0.138\" which would be \"13.8%2F100=%2213.8%25+w%2Fw%22\" .
\n" ); document.write( "That solution will be more dense than water, but not by much.
\n" ); document.write( "Its density at common room temperatures will be 1.06 g/mL. (I look that up when I need to).
\n" ); document.write( "So, your 16% w/v solution would weigh \"%2850mL%29%28%221.06+g+%2F+mL%22%29=about+52.8g\" ,
\n" ); document.write( "with a w/w ratio of \"8%2F52.8=about0.152\" .
\n" ); document.write( "That approximate ratio is \"15.2%2F100=%2215.2%25%22\" , and that is the %w/w.\r
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\n" ); document.write( "\n" ); document.write( "A DIFFERENT PROBLEM:
\n" ); document.write( "However, if you mix 8g dextrose and 50mL of water, for a final weight of about \"6g%2B50g=8g\" ,
\n" ); document.write( "that is a different math problem.
\n" ); document.write( "If you are a pharmaceutical formulator or a chemical engineer that is your problem.
\n" ); document.write( "The final volume will be more than 50mL, but not quite 58mL.
\n" ); document.write( "The concentration as %w/w would be \"8g%2F%2258+g%22=approximately+0.138\" ,
\n" ); document.write( "which is 13.8%w/w.
\n" ); document.write( "A table of densities, or \"specific gravities\" would tell you that its density would be about \"%221.06+g+%2F+mL%22\" too.
\n" ); document.write( "That means its volume would be
\n" ); document.write( "\"58g%2F%221.06+g+%2F+mL%22=about54.7mL\" .
\n" ); document.write( "That would make its (solute weight)/(total volume) ratio
\n" ); document.write( "about \"8%2F54.7=about+0.146\"
\n" ); document.write( "and its %w/v concentration \"14.6%2F100=%2214.6%25%22\" .\r
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