document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1108214>Question 1108214</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A strange announcement was made on the radio about a local election with three candidates: Mrs Allan, Mr Baxter and Ms Campbell.<BR>\n" );
document.write( "“Mrs Allan beat Mr Baxter by one eighth of the total votes cast.<BR>\n" );
document.write( "Mr Baxter beat Ms Campbell by a seventh of the total votes cast.<BR>\n" );
document.write( "The votes cast for Mrs Allan was 350 fewer than 3 times Ms Campbell's votes.”<BR>\n" );
document.write( "How many votes did each candidate get?\r<BR>\n" );
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document.write( "I know this is a simultaneous equation problem, but I am not very good at them. I keep going round in circles and cannot figure out what the next step is.\r<BR>\n" );
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document.write( "Thank you in advance! Your help is much appreciated! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #723238 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=723238\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Total votes cast=x<BR>\n" );
document.write( "A-B=(1/8)x<BR>\n" );
document.write( "B-C=(1/7)x<BR>\n" );
document.write( "A=3C-350<BR>\n" );
document.write( "A+B+C=x<BR>\n" );
document.write( "A=B +(1/8)x from the first<BR>\n" );
document.write( "B+(1/8)x+B+C=x<BR>\n" );
document.write( "2B+C=(7/8)x<BR>\n" );
document.write( "B-C=(1/7)x from the second<BR>\n" );
document.write( "3B=(57/56)x using common denominator of 56<BR>\n" );
document.write( "B=(19/56)x<BR>\n" );
document.write( "Then C=(11/56)x substituting into B-C=(1/7)x<BR>\n" );
document.write( "A=(26/56)x<BR>\n" );
document.write( "Those three =x<BR>\n" );
document.write( "A=3C-350, so (26/56)x=(33/56)x-350, and -(7/56)x=-350=(-1/8)x, so that x=2800 votes <BR>\n" );
document.write( "A got 26/56 of them or 1300<BR>\n" );
document.write( "B got 19/56 of them or 950<BR>\n" );
document.write( "C got 11/56 of them or 550<BR>\n" );
document.write( "ANSWER<BR>\n" );
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