document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1108183>Question 1108183</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 56cm. The width is 8cm. less than the length. Find its area. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #723183 by </B><A HREF=/tutors/aboutme.mpl?userid=rumessa><B>rumessa(13)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rumessa><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=723183\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  length =l<BR>\n" );
document.write( "width = l-8<BR>\n" );
document.write( "p = 56<BR>\n" );
document.write( "p= 2(l+w)<BR>\n" );
document.write( "56 = 2 ( l +l -8 )<BR>\n" );
document.write( "56 = 2( 2l -8 )<BR>\n" );
document.write( "56 = 4i -16<BR>\n" );
document.write( "4l = 56=16<BR>\n" );
document.write( "4l = 72<BR>\n" );
document.write( "l= 18<BR>\n" );
document.write( "w = l - 8<BR>\n" );
document.write( "w = 18 - 8<BR>\n" );
document.write( "w = 10<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );