document.write( "Question 1108183: The perimeter of a rectangle is 56cm. The width is 8cm. less than the length. Find its area. \n" ); document.write( "
Algebra.Com's Answer #723167 by math_helper(2461)\"\" \"About 
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\n" ); document.write( "P = 2L + 2W
\n" ); document.write( "56 = 2L + 2(L-8) <<<— Width is Length-8cm\r
\n" ); document.write( "\n" ); document.write( "56 = 2L + 2L - 16\r
\n" ); document.write( "\n" ); document.write( "Can you solve it from here? You will need to find L, then W (=L-8) and then compute L*W to get area.\r
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