document.write( "Question 1108155: A bus starts with 6 people and stops at 10 different stops, how many different ways can the 6 people depart if any passenger can depart at any bus stop
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Algebra.Com's Answer #723141 by ikleyn(52781)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "1-st person can go out at any of 10 bus stops - 10 opportunities.\r\n" );
document.write( "2-nd person can go out at any of 10 bus stops - 10 independent opportunities.\r\n" );
document.write( "3-rd person can go out at any of 10 bus stops - 10 independent opportunities.\r\n" );
document.write( "4-th person can go out at any of 10 bus stops - 10 independent opportunities.\r\n" );
document.write( "5-th person can go out at any of 10 bus stops - 10 independent opportunities.\r\n" );
document.write( "6-th person can go out at any of 10 bus stops - 10 independent opportunities.\r\n" );
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document.write( "In all, there are  \"10%5E6\" different ways.\r\n" );
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document.write( "Same number of ways as how many 6-letter words do exist comprising of 10 given letters (symbols) of the alphabet, if letters repetition is allowed.\r\n" );
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\n" ); document.write( "I just solved it at least two times in this forum.\r
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\n" ); document.write( "\n" ); document.write( "See the lesson \r
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\n" ); document.write( "\n" ); document.write( "Also,  you have this free of charge online textbook in ALGEBRA-II in this site\r
\n" ); document.write( "\n" ); document.write( "    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.\r
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\n" ); document.write( "\n" ); document.write( "The referred lesson is the part of this online textbook under the topic  \"Combinatorics: Combinations and permutations\". \r
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\n" ); document.write( "\n" ); document.write( "Save the link to this textbook together with its description\r
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\n" ); document.write( "\n" ); document.write( "Free of charge online textbook in ALGEBRA-II
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\n" ); document.write( "\n" ); document.write( "into your archive and use when it is needed.\r
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