document.write( "Question 1108025: Suppose that a cyclist began a 352
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\n" ); document.write( "mi ride across a state at the western edge of the​ state, at the same time that a car traveling toward it leaves the eastern end of the state. If the bicycle and car met after 5.5
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\n" ); document.write( "hr and the car traveled 32.8
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\n" ); document.write( "mph faster than the​ bicycle, find the average rate of each \n" ); document.write( "
Algebra.Com's Answer #723131 by ankor@dixie-net.com(22740)\"\" \"About 
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Suppose that a cyclist began a 352 mi ride across a state at the western edge of the​ state, at the same time that a car traveling toward it leaves the eastern end of the state.
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\n" ); document.write( " If the bicycle and car met after 5.5 hr and the car traveled 32.8 mph faster than the​ bicycle,
\n" ); document.write( " find the average rate of each
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\n" ); document.write( "let s = the speed of the bike
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\n" ); document.write( "(s+32.8) = the speed of the car
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\n" ); document.write( "Both travel for 5.5 hrs and the sum of their distances is 352 mi
\n" ); document.write( "(dist = time * speed)
\n" ); document.write( "5.5s + 5.5(s+32.8) = 352
\n" ); document.write( "5.5s + 5.5s + 180.4 = 352
\n" ); document.write( "11s = 352 - 180.4
\n" ); document.write( "11s = 171.6
\n" ); document.write( "s = 171.6/11
\n" ); document.write( "s = 15.6 mph is the speed of the bike
\n" ); document.write( "then, obviously
\n" ); document.write( "15.6 + 32.8 = 48.4 mph is the speed of the car
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\n" ); document.write( "Confirm this, find the distance each traveled
\n" ); document.write( "5.5*15.6 = 85.8 mi
\n" ); document.write( "5.5*48.4 = 266.2 mi
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\n" ); document.write( "total dist: 352.0 \n" ); document.write( "
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