document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1108127>Question 1108127</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the following system of linear equations using the substitution method:\r<BR>\n" );
document.write( "\n" );
document.write( "3x-2y=18<BR>\n" );
document.write( "5x+10y=-10\r<BR>\n" );
document.write( "\n" );
document.write( "Express answer as an ordered pair </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #723116 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=723116\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve the following system of linear equations using the substitution method:\r<BR>\n" );
document.write( "\n" );
document.write( "3x-2y=18<BR>\n" );
document.write( "5x+10y=-10--> x + 2y = -2 --> x = -2y - 2<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Sub for x in the 1st eqn<BR>\n" );
document.write( "3(-2y-2) - 2y = 18<BR>\n" );
document.write( "-6y - 6 - 2y = 18<BR>\n" );
document.write( "-8y = 24<BR>\n" );
document.write( "y = -3<BR>\n" );
document.write( "===========<BR>\n" );
document.write( "etc<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );