document.write( "Question 99292: Hi, I'm having problems figuring these 2 problems out. I have been understanding similar problems, but don't know what I did wrong. Could you please help me? Thanks!!~Leslie\r
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document.write( "Problem# 39: Solve for C: 1/2(c+8)=1/4c\r
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document.write( "Problem# 41: Solve for A:
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Algebra.Com's Answer #72309 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Problem# 39: \n" ); document.write( "Solve for C: \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Get rid of the denominator, multiply equation by 4: \n" ); document.write( "4* \n" ); document.write( ": \n" ); document.write( "Cancel out the denominators and you have; \n" ); document.write( "2(c+8) = 1c \n" ); document.write( "2c + 16 = c; multiply what's inside the brackets \n" ); document.write( "2c - c = -16; subtract c and 16 from both sides \n" ); document.write( "c = -16 \n" ); document.write( ": \n" ); document.write( "Check solution by substitution in original equation: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "-4 = -4 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Problem# 41: Solve for A: \n" ); document.write( " \n" ); document.write( "; \n" ); document.write( "Multiply equation by 5 to get rid of the denominators: \n" ); document.write( "5* \n" ); document.write( ": \n" ); document.write( "1a + 40 = -3(a-15) \n" ); document.write( "a + 40 = -3a + 45 \n" ); document.write( "a + 3a = 45 - 40 \n" ); document.write( "4a = 5 \n" ); document.write( "a = 5/4 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution using 1.25 as 5/4: \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( ".25 + 8 = \n" ); document.write( "8.25 = 8.25 confirms out solution \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " |