document.write( "Question 1108061: Using elimination method what is x and y in the equation:\r
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document.write( "2x/3 + y/6 = 1
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document.write( "x/6 - y/2 = 1 \n" );
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Algebra.Com's Answer #723070 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "2x/3 + y/6 = 1 \n" ); document.write( "x/6 - y/2 = 1 \n" ); document.write( "================ \n" ); document.write( "Multiply by 6 to eliminate fractions. \n" ); document.write( "4x + y = 6 \n" ); document.write( "x - 3y = 6 \n" ); document.write( "------ \n" ); document.write( "Multiply the 1st eqn by 3 \n" ); document.write( "12x +3y = 18 \n" ); document.write( "x - 3y = 6 \n" ); document.write( "------------------- Add \n" ); document.write( "13x = 24 \n" ); document.write( "x = 24/13 \n" ); document.write( "y = -18/13 \n" ); document.write( " |