document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1107998>Question 1107998</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a builder has designed a rectangular floor area to be 228 square feet. The builders clients want the floor to be 243 square feet, which can be accomplished by adding 2 feet to the width and 1 foot to the length of the original plans. What are the dimensions of the floor in the original plans?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #723061 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=723061\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> i don't believe there is a solution to this.\r<BR>\n" );
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document.write( "i tried solving algebraically and then i tried solving graphically and both times i got no solution.\r<BR>\n" );
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document.write( "algebraically i got complex roots.\r<BR>\n" );
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document.write( "graphically i got no intersection.\r<BR>\n" );
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document.write( "i then used excel to see if i could find the minimum increase in area when i add 2 to one of the dimensions and i add 1 to the other dimension.\r<BR>\n" );
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document.write( "excel said minimum area with the increased dimensions was somewhere around 272.8.\r<BR>\n" );
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document.write( "i then took the square root of 228 and added the square root of 2 to it and then squared the result and i got (sqrt(228) + sqrt(15))^2 = 272.708313.\r<BR>\n" );
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document.write( "this appears to be the minimum area increase which means that 243 is not possible given the requirements of the problem.\r<BR>\n" );
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document.write( "my guess is that there is no solution to this problem as presented.\r<BR>\n" );
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