document.write( "Question 1107951: A museum borrows $2,000,000 at simple annual interest to purchase new
\n" ); document.write( "exhibits. Let x represent the amount borrowed at 7%, y represent the amount borrowed at 8.5%, and z represent the amount borrowed at 9.5%. Set up a system of linear equations to determine how much is borrowed at each rate given that the total annual interest is $169,750 and the amount borrowed at 8.5% is four times the amount borrowed at 9.5%. \n" ); document.write( "
Algebra.Com's Answer #723002 by addingup(3677)\"\" \"About 
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Let the amount borrowed at 9.5% be x. Now we have:
\n" ); document.write( "at 9.5% = x
\n" ); document.write( "at 8.5% = 4x
\n" ); document.write( "at 7% = 2,000,000 - 5x
\n" ); document.write( "0.095x + 0.085(4x) + 0.07(2,000,000-5x) = 169,750
\n" ); document.write( "0.095x + 0.34x + 140,000 - 0.35x = 169,750
\n" ); document.write( "0.085x = 29,750
\n" ); document.write( "x = 350,000
\n" ); document.write( "So the museum borrowed:
\n" ); document.write( "At 9.5% = 350K
\n" ); document.write( "At 8.5% = 350*4 = 1,400,000
\n" ); document.write( "At 7% = 2,000,000 - 5(350,000) = 250,000
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\n" ); document.write( "Total borrowed
\n" ); document.write( "350,000 + 1,400,000 + 250,000 = 2,000,000 Correct
\n" ); document.write( "--------------------------------------
\n" ); document.write( "Interest paid:
\n" ); document.write( "0.095(350,000) + 0.085(1,400,000) + 0.07(250,000) = 169,750 Correct \n" ); document.write( "
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