document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=14434>Question 14434</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3[3-3(x+1)]+1=2(-14-x)+2x+14 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #7230 by </B><A HREF=/tutors/aboutme.mpl?userid=atif.muhammad><B>atif.muhammad(135)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=atif.muhammad><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=7230\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3[3-3(x+1)]+1=2(-14-x)+2x+14\r<BR>\n" );
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document.write( "3[3 - 3x - 3] + 1 = - 28 - 2x + 2x + 14\r<BR>\n" );
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document.write( "3[3x] + 1 = - 14 --> forgot the -ve sign in front of the 3x term (LongJonSilver)\r<BR>\n" );
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document.write( "9x + 1 = -14\r<BR>\n" );
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document.write( "9x = -15\r<BR>\n" );
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document.write( "3x = -5\r<BR>\n" );
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document.write( "x = -5/3 </SPAN>\n" );
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