document.write( "Question 1107833: I'm a student of MSciEd secondary math.. I just wanna ask if you could answer the problem set that my instructor in mathed 235 haave given us.. the question is
\n" );
document.write( "Let ABCD be trapezoid with the sides AD and BC parallel to each other and perpendicular to AB. moreover, assume that BC=2AD. the points P and Q on the side of AB divide it into three equal segments, and P is between A and Q. Similarly, the points R and S on the side of CD divide it into three equal segments, and R is between D and S. Let a1 be the area of the triangle, triangle AQR and let a2 be the area of the triangle, triangle PBS. Find the ratio a1/a2. \n" );
document.write( "
Algebra.Com's Answer #722972 by math_helper(2461)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "\n" ); document.write( "Area a1 = area of AQR \n" ); document.write( "Area a2 = area of PBS \n" ); document.write( "-- \n" ); document.write( "Base_AQR = (2/3)AB \n" ); document.write( "Base_PBS = (2/3)AB \n" ); document.write( "— \n" ); document.write( "The heights are measured along a line parallel to the x-axis, and note that the projection of DR onto the x-axis has length equal to (1/3)AD, while the projection of SD onto the x-axis has length (2/3)AD.\r \n" ); document.write( "\n" ); document.write( "Height_AQR = AD + (1/3)AD = (4/3)AD \n" ); document.write( "Height_PBS = AD + (2/3)AD = (5/3)AD\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-- \n" ); document.write( "Area_a1 = (1/2) (2/3)AB * (4/3)AD \n" ); document.write( "Area_a2 = (1/2) (2/3)AB * (5/3)AD \n" ); document.write( "—\r \n" ); document.write( "\n" ); document.write( "Answer: Area_a1/Area_a2 = 4/5\r \n" ); document.write( "\n" ); document.write( "—\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |