document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1107907>Question 1107907</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rancher is building a pen using 150 feet of fencing. The pen will be enclosed on 3 sides, with the fourth side shared by an already existing pen. What is the function of the area of the new pen? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #722962 by </B><A HREF=/tutors/aboutme.mpl?userid=JThomson><B>JThomson(12)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JThomson><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JThomson><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=722962\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Assuming the pen has one of its lengths shared be existing pen then;\r<BR>\n" );
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document.write( "2B + L = perimeter\r<BR>\n" );
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document.write( "2B + L = 150\r<BR>\n" );
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document.write( "But L=150-2B or B = 1/2(150-L)\r<BR>\n" );
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document.write( "So Area of the pen is;\r<BR>\n" );
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document.write( "A = B(150-2B) or 1/2(150L-L^2)\r<BR>\n" );
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document.write( "= 150B-2B^2 where L and B are the Length and \r<BR>\n" );
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document.write( "breadth respectively.\r<BR>\n" );
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document.write( "Note that Area (A) could also be 1/2(150B-B^2) \r<BR>\n" );
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document.write( "when one of the widths is shared by a pen in \r<BR>\n" );
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document.write( "which case 2L+B=150\r<BR>\n" );
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document.write( " </SPAN>\n" );
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