document.write( "Question 1107916: The sum of the square of a positive number and the square of 3 more than the number is 29.can you show steps how to work this out and the correct answer ? \n" ); document.write( "

Algebra.Com's Answer #722957 by JThomson(12) $\"\"$ $\"About$

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Let the number be 'x'\r
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\n" ); document.write( "\n" ); document.write( "The square of the number is x^2 \r
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\n" ); document.write( "\n" ); document.write( "3 more than the number is (x+3);\r
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\n" ); document.write( "\n" ); document.write( "The square of 3 more than the number is (x+3)^2\r
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\n" ); document.write( "\n" ); document.write( "So x^2+(x+3)^2 = 29\r
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\n" ); document.write( "\n" ); document.write( "x^2+(x^2+6x+9)-29=0\r
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\n" ); document.write( "\n" ); document.write( "2x^2+6x-20=0\r
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\n" ); document.write( "\n" ); document.write( "x^2+3x-10=0\r
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\n" ); document.write( "\n" ); document.write( "(x+5)(x-2)=0\r
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\n" ); document.write( "\n" ); document.write( "x=-5 and 2\r
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\n" ); document.write( "\n" ); document.write( "But since x must be a positive number, x=2 .\r
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