document.write( "Question 1107809: Air-USA has a policy of booking as many as 15 persons on an airplane that can seat only 14. (Past studies have revealed that only 83% of the booked passengers actually arrive for the flight.)\r
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document.write( "Find the probability that if Air-USA books 15 persons, not enough seats will be available.
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document.write( "prob =
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document.write( " (round to 4 decimal places)\r
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document.write( "Is this probability low enough so that overbooking is not a real concern for passengers if you define unusual as 5% or less?
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document.write( "yes, it is low enough not to be a concern
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document.write( "no, it is not low enough to not be a concern\r
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document.write( "What about defining unusual as 10% or less?
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document.write( "yes, it is low enough not to be a concern
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document.write( "no, it is not low enough to not be a concern \n" );
document.write( "
Algebra.Com's Answer #722949 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Air-USA has a policy of booking as many as 15 persons on an airplane that can seat only 14. (Past studies have revealed that only 83% of the booked passengers actually arrive for the flight.) \n" ); document.write( "Find the probability that if Air-USA books 15 persons, not enough seats will be available. \n" ); document.write( "prob = (0.83)^15 = 0.0611 \n" ); document.write( "(round to 4 decimal places) \n" ); document.write( "Is this probability low enough so that overbooking is not a real concern for passengers if you define unusual as 5% or less? \n" ); document.write( "------- \n" ); document.write( "no, it is not low enough to not be a concern \n" ); document.write( "---------------------- \n" ); document.write( "What about defining unusual as 10% or less? \n" ); document.write( "yes, it is low enough not to be a concern\r \n" ); document.write( "\n" ); document.write( "---- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "---------- \n" ); document.write( " |