document.write( "Question 1107809: Air-USA has a policy of booking as many as 15 persons on an airplane that can seat only 14. (Past studies have revealed that only 83% of the booked passengers actually arrive for the flight.)\r
\n" ); document.write( "\n" ); document.write( "Find the probability that if Air-USA books 15 persons, not enough seats will be available.
\n" ); document.write( "prob =
\n" ); document.write( " (round to 4 decimal places)\r
\n" ); document.write( "\n" ); document.write( "Is this probability low enough so that overbooking is not a real concern for passengers if you define unusual as 5% or less?
\n" ); document.write( "yes, it is low enough not to be a concern
\n" ); document.write( "no, it is not low enough to not be a concern\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "What about defining unusual as 10% or less?
\n" ); document.write( "yes, it is low enough not to be a concern
\n" ); document.write( "no, it is not low enough to not be a concern
\n" ); document.write( "

Algebra.Com's Answer #722949 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Air-USA has a policy of booking as many as 15 persons on an airplane that can seat only 14. (Past studies have revealed that only 83% of the booked passengers actually arrive for the flight.)
\n" ); document.write( "Find the probability that if Air-USA books 15 persons, not enough seats will be available.
\n" ); document.write( "prob = (0.83)^15 = 0.0611
\n" ); document.write( "(round to 4 decimal places)
\n" ); document.write( "Is this probability low enough so that overbooking is not a real concern for passengers if you define unusual as 5% or less?
\n" ); document.write( "-------
\n" ); document.write( "no, it is not low enough to not be a concern
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\n" ); document.write( "What about defining unusual as 10% or less?
\n" ); document.write( "yes, it is low enough not to be a concern\r
\n" ); document.write( "\n" ); document.write( "----
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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