document.write( "Question 1107840: Two boats left the harbour at the same time. One travelled at 10km/h on a bearing pf N47'E. The other travelled at 8km/h on a bearing of N79'E. How far apart were the boats after 45 min? Round your answer to the nearest tenth of a kilometre. \n" ); document.write( "
| Algebra.Com's Answer #722891 by ankor@dixie-net.com(22740)     You can put this solution on YOUR website! Two boats left the harbour at the same time. \n" ); document.write( " One travelled at 10km/h on a bearing pf N47'E. \n" ); document.write( " The other travelled at 8km/h on a bearing of N79'E. \n" ); document.write( " How far apart were the boats after 45 min? \n" ); document.write( " Round your answer to the nearest tenth of a kilometre. \n" ); document.write( ": \n" ); document.write( "the angle between the paths of the two boats: 79 - 47 = 32 degrees \n" ); document.write( "find how far each boat has traveled in 45 min ( \n" ); document.write( "Boat l: \n" ); document.write( "Boat 2: \n" ); document.write( "Use the law of cosines a^2 = b^2 + c^2 - 2(b*c)*cos(A) where \n" ); document.write( "a = distance between the boats after 45 min \n" ); document.write( "b = 7.5 km \n" ); document.write( "c = 6 km \n" ); document.write( "A = 32 degrees \n" ); document.write( "a^2 = 7.5^2 + 6^2 - 2(7.5*6)*cos(32) \n" ); document.write( "a^2 = 56.25 + 36 - 2(45)*.848 \n" ); document.write( "Do the math, I got: \n" ); document.write( "a = \n" ); document.write( "a = 4.0 km \n" ); document.write( " |