document.write( "Question 1107866: I need some help describing and correcting the error.\r
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document.write( "3/x + 6/x+3 =8/x+1\r
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document.write( "LCD=x(x+3)(x+1)
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document.write( "3(x+3)(x+1)+6x(x+1)=8
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document.write( "3(x^2+4x+3)+6x^2+6x=8
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document.write( "3x^2+12x+9+6x^2+6x=8
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document.write( "9x^2+18x+1=0\r
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document.write( "X=Square root of -18 plus or minus square root of 18^2-4(9)(1)/2(9)\r
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document.write( "=Square root -18 plus or minus square root 288/18 = -18 plus of minus 12 square root 2 / 18
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document.write( "X=-3 plus or minus 2 square root 2 / 3\r
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document.write( "thanks. \n" );
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Algebra.Com's Answer #722886 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 3/x + 6/x+3 =8/x+1 \n" ); document.write( "LCD=x(x+3)(x+1) \n" ); document.write( "--- \n" ); document.write( "Multiply both sides by the LCD to get:: \n" ); document.write( "3(x+3)(x+1)+6x(x+1)=8x(x+1) \n" ); document.write( "---- \n" ); document.write( "3(x^2+4x+3) + 6x^2+6x = 8x^2+8x \n" ); document.write( "----------- \n" ); document.write( "9x^2 + 18x + 9 = 8x^2 + 8x \n" ); document.write( "---- \n" ); document.write( "x^2 +10x + 9 = 0 \n" ); document.write( "---- \n" ); document.write( "(x+9)(x+1) = 0 \n" ); document.write( "--- \n" ); document.write( "Ans:: x = -9 or x = -1 \n" ); document.write( "------------------------ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------- \n" ); document.write( " |