document.write( "Question 1107798: How many gallons of a 80​% antifreeze solution must be mixed with 80 gallons of 20​% antifreeze to get a mixture that is 70​% ​antifreeze? Use the​ six-step method. \n" ); document.write( "
Algebra.Com's Answer #722825 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
What six steps?\r
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\n" ); document.write( "\n" ); document.write( "x, how many gallons of 80% antifreez\r
\n" ); document.write( "\n" ); document.write( "PRESENT: 80 gallons of 20% antifreeze\r
\n" ); document.write( "\n" ); document.write( "WANT: 70% antifreeze\r
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\n" ); document.write( "\n" ); document.write( "\"%2820%2A80%2B80%2Ax%29%2F%2880%2Bx%29=70\", Basic Equation\r
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\n" ); document.write( "\n" ); document.write( "-\r
\n" ); document.write( "\n" ); document.write( "\"20%2A80%2B80x=70%2A%2880%2Bx%29\"
\n" ); document.write( "\"2%2A80%2B8x=7%2880%2Bx%29\"
\n" ); document.write( "\"2%2A80%2B8x=7%2A80%2B7x\"
\n" ); document.write( "\"x=5%2A80\"
\n" ); document.write( "\"highlight%28x=400%29\"
\n" ); document.write( "Four Hundred Gallons of 80% material be added.\r
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\n" ); document.write( "\n" ); document.write( "CHECK?\r
\n" ); document.write( "\n" ); document.write( "\"%2820%2A80%2B80%2A400%29%2F480\"\r
\n" ); document.write( "\n" ); document.write( "\"%282%2A80%2B8%2A400%29%2F48\"\r
\n" ); document.write( "\n" ); document.write( "\"70\"\r
\n" ); document.write( "\n" ); document.write( "\"okay\"
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