document.write( "Question 1107792: A woman has a total of $10,000 to invest. She invests part of the money in an account that pays 10% per year and the rest in an account that pays 12% per year. If the interest earned in the first year is $1080, how much did she invest in each account? \n" ); document.write( "
Algebra.Com's Answer #722819 by addingup(3677)![]() ![]() You can put this solution on YOUR website! 0.10x + 0.12(10,000 - x) = 1080 \n" ); document.write( "0.10x + 1,200 - 0.12x = 1080 \n" ); document.write( "-0.02x = -120 divide, and remember that -/- = + so for the purpose of division you can ignore the negative sign \n" ); document.write( "x = 6,000 \n" ); document.write( "She invested 6,000 at 10% and 4,000 at 12% \n" ); document.write( " |