document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1107749>Question 1107749</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A towns population has been increasing at a constant (linear) rate. In 2010 the population was 46,020. By 2012 the population has increased to 52,070. Assume this trend continues. \r<BR>\n" );
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document.write( "The towns predicted population in 2020 is?<BR>\n" );
document.write( "In what year will the towns predicted population be 103495? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #722818 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=722818\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In two years, the population increased 6050.<BR>\n" );
document.write( "The slope is 6050/2=3025.<BR>\n" );
document.write( "In 2020, 10 years later, the population will increase 3025*10 or 30,250 from 2010, to 76,270.<BR>\n" );
document.write( "103495=46020+3025x, which is the formula where x=years from 2010<BR>\n" );
document.write( "57475=3025x<BR>\n" );
document.write( "x=19 years<BR>\n" );
document.write( "2029. ANSWER<BR>\n" );
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