document.write( "Question 1107759: The father is 38 years older than the son. Ten years ago he was twice the age of the son. How old is the father and son now. \n" ); document.write( "
Algebra.Com's Answer #722782 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! let f be the father's age and s be the son's age \n" ); document.write( ": \n" ); document.write( "f = s +38 \n" ); document.write( ": \n" ); document.write( "s +38 -10 = 2(s -10) \n" ); document.write( ": \n" ); document.write( "s +38 -10 = 2s -20 \n" ); document.write( ": \n" ); document.write( "s = 48 \n" ); document.write( ": \n" ); document.write( "************************************************* \n" ); document.write( "father is 86 and son is 48 \n" ); document.write( ": \n" ); document.write( "10 yeas ago the father was 76 and the son was 38 \n" ); document.write( ": \n" ); document.write( "76 = 2 * 38 = 76 \n" ); document.write( "************************************************* \n" ); document.write( ": \n" ); document.write( " |