document.write( "Question 1107725: ship A is due west of a lighthouse. ship B is 12 km southof ship A. from ship B, the bearing to the lighthouse is N63°20'E, how far is ship A from the lighthouse? answer \n" ); document.write( "
Algebra.Com's Answer #722748 by Theo(13342)\"\" \"About 
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the lighthouse and ship A and ship B make a right triangle as shown below:\r
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\n" ); document.write( "\n" ); document.write( "that triangle is labeled ABC, where C is the position of the lighthouse.\r
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\n" ); document.write( "\n" ); document.write( "from ship B, the bearing to the lighthouse is north 63 degrees 20 minutes east.\r
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\n" ); document.write( "\n" ); document.write( "63 degrees 20 minutes is equal to 63 and 1/3 degrees because 20 seconds / 60 = 1/3 minutes.\r
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\n" ); document.write( "\n" ); document.write( "that angle is shown in the following diagram.\r
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\n" ); document.write( "\n" ); document.write( "tangent of 63 and 1/3 degrees is equal to opposite side divided by adjacent side.\r
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\n" ); document.write( "\n" ); document.write( "that makes tangent of 63 and 1/3 degrees = x / 12.\r
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\n" ); document.write( "\n" ); document.write( "multiply both sides of this equation by 12 to get 12 * tan(63 and 1/3) = x\r
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\n" ); document.write( "\n" ); document.write( "solve for x to get x = 23.89396451\r
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\n" ); document.write( "\n" ); document.write( "here's a reference on bearing you might find helpful.\r
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\n" ); document.write( "\n" ); document.write( "http://www.mathsteacher.com.au/year10/ch15_trigonometry/11_directions/23dir.htm\r
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\n" ); document.write( "\n" ); document.write( "your north line in the diagram is represented by the line segment AB.
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