document.write( "Question 1107720: The value of a number of dimes and quarters is $1.25. If the number of dimes was
\n" ); document.write( "doubled and the number of quarters was increased by 5, the value would be $3.00.
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Algebra.Com's Answer #722740 by Edwin McCravy(20056) $\"\"$ $\"About$

You can put this solution on YOUR website!

Josgarithetic above gave the correct system of equations but gave no \r\n" );
document.write( "explanation as to how he got them.

The value of a number of dimes and quarters is $1.25.

0.10D + 0.25Q = 1.25

If the number of dimes was doubled and the number of quarters was increased by 5, the value would be $3.00.

0.10(2D) + 0.25(Q+5) = 3.00\r\n" );
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document.write( "Simplify each equation:\r\n" );
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document.write( "0.10D + 0.25Q = 1.25  <-- move decimals two places right\r\n" );
document.write( "    10D + 25Q = 125   <-- divide through by 5\r\n" );
document.write( "      2D + 5Q = 25\r\n" );
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document.write( "0.10(2D) + 0.25(Q+5) = 3.00  <--move decimals two places right\r\n" );
document.write( "    10(2D) + 25(Q+5) = 300   <--divide through by 5\r\n" );
document.write( "      2(2D) + 5(Q+5) = 60    <--simplify\r\n" );
document.write( "        4D + 5Q + 25 = 60    <--subtract 25 from both sides\r\n" );
document.write( "             4D + 5Q = 35   \r\n" );
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document.write( "Solve the system of equations:\r\n" );
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document.write( "You'll get 5 dimes and 3 quarters.\r\n" );
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document.write( "Edwin

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