document.write( "Question 1107699: A student is to mark out a rectangular field so that its perimeter is 400 metres. Let x be the length of the field. Find a formula for the area, A, of the field in terms of x and by graphing the formula on a number plane, find the dimensions of the field which would make the area a maximum. \n" ); document.write( "
Algebra.Com's Answer #722722 by addingup(3677)\"\" \"About 
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2L + 2W = 400
\n" ); document.write( "simplifying:
\n" ); document.write( "L + W = 200
\n" ); document.write( "L = 200 - W
\n" ); document.write( "Equation for the area:
\n" ); document.write( "A = (200 - W) x W = 200W - W^2
\n" ); document.write( "So we have a negative quadratic, which means we'll have an upside down parabola where the vertex is the maximum.
\n" ); document.write( "Quadratic equation in the format y = ax2 + bx + c :
\n" ); document.write( "A = –W^2 + 200W
\n" ); document.write( "The vertex of the parabola is the point (h, k) where h = -b/2a:
\n" ); document.write( "h = -200/(2 x (-1)) = -200/-2 = 100
\n" ); document.write( "To find k, let's plug 100 for W:
\n" ); document.write( "k = -100^2 + 200(100) = -10,000 + 20,000 = 10,000
\n" ); document.write( "OK, so now we know that h (the maximizing width) is 100, and k (the maximum area) is 10,000. So the shape of our rectangle will be the square:
\n" ); document.write( "2L + 2W = 400
\n" ); document.write( "2(100) + 2(100) = 400
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\n" ); document.write( "NOTE: Of the rectangles (four sided figures with four right angles), the square will always give you the largest area.
\n" ); document.write( "And of all geometric figures, the one that will give you the biggest area is the circle. IF your figure was a circle, the area you would get would be:
\n" ); document.write( "A = C^2/4Pi where C is the perimeter
\n" ); document.write( "A = 400^2/12.56 12,739
\n" ); document.write( "Happy learning,
\n" ); document.write( "John\r
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