document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1107690>Question 1107690</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The point P(x, y) lies on the parabola y=(1/2)x^2. Find this point such that the sum S of the abscissa and ordinate is a minimum.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #722716 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=722716\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The point P(x, y) lies on the parabola y=(1/2)x^2. Find this point such that the sum S of the abscissa and ordinate is a minimum. <BR>\n" );
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document.write( "Sum of x and (1/2)x^2 = (1/2)x^2+x<BR>\n" );
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document.write( "Mimimum occurs where x = -b/(2a) = -1/(2) = -1/2-Then y = (1/2)(1/2)^2 -(1/2) = (1/2)(1/4)-(1/2) = (1/8)-(1/2) = (2-8)/16 = -3/8<BR>\n" );
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document.write( "Minimum sum = (-1/2)+(-3/8) = (-4/8)+(-3/8) = -7/8<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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