document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1107698>Question 1107698</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The equation of the path of a cricket ball thrown at an angle of 45 degrees, with the horizontal is y = x - (x^2)/50 where x metres and y metres are the horizontal distance travelled and vertical height respectively. Calculate the greatest vertical height reached and the total horizontal distance travelled.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #722715 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=722715\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The equation of the path of a cricket ball thrown at an angle of 45 degrees, with the horizontal is y = x - (x^2)/50 where x metres and y metres are the horizontal distance traveled and vertical height respectively. Calculate the greatest vertical height reached and the total horizontal distance traveled. <BR>\n" );
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document.write( "Max occurs when 1-(2/50)x = 0<BR>\n" );
document.write( "(1/25)x = 1<BR>\n" );
document.write( "x = 25 metres<BR>\n" );
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document.write( "max height occurs at f(25)= [25 - (25^2)/50]= 25 - (625/50) = 25-12.5 = 12.5 metres<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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