document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1107699>Question 1107699</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A student is to mark out a rectangular field so that its perimeter is 400 metres. Let x be the length of the field. Find a formula for the area, A, of the field in terms of x and by graphing the formula on a number plane, find the dimensions of the field which would make the area a maximum.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #722713 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=722713\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> : A student is to mark out a rectangular field so that its perimeter is 400 metres. Let x be the length of the field. Find a formula for the area, A, of the field in terms of x and by graphing the formula on a number plane, find the dimensions of the field which would make the area a maximum. <BR>\n" );
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document.write( "Draw a rectangle.  Mark a side \"x\". Mark the side opposite \"x\".<BR>\n" );
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document.write( "The sum of the 2 remaining sides is 400-2x<BR>\n" );
document.write( "Each of those remaining sides is (400-2x)/2 = 200-x<BR>\n" );
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document.write( "Area = x(200-x) = 200x - x^2<BR>\n" );
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document.write( "Maximum occurs where 200-2x = 0<BR>\n" );
document.write( "x = 100<BR>\n" );
document.write( "200-x = 100<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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