document.write( "Question 1107683: How to prove that \"sinxcos%5E3x-cosxsin%5E3x=%281%2F4%29%28sin4x%29\"? \n" ); document.write( "
Algebra.Com's Answer #722712 by ikleyn(52848)\"\" \"About 
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document.write( "  \"sinxcos%5E3x-cosxsin%5E3x=%281%2F4%29%28sin4x%29\" = \"sin%28x%29%2Acos%28x%29%2A%28cos%5E2%28x%29-sin%5E2%28x%29%29\" = \r\n" );
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document.write( "     Use the basic trigonometric formulas  sin(x)*cos(x) = \"%281%2F2%29%2Asin%282x%29\",   cos^2(x)-sin^2(x) = cos(2x)  to get\r\n" );
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document.write( "= \"%281%2F2%29%2Asin%282x%29%2Acos%282x%29\" =  //use again  sin(2x)*cos(2x) = \"%281%2F2%29%2Acos%284x%29\"  to get //   = \"%281%2F4%29%2Acos4x%29\".\r\n" );
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document.write( "That's all.\r\n" );
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