document.write( "Question 99302: Ronald has a 12% solution of the fertilizer Super Grow. How much pure super grow should he add to the mixture to get 32oz of a 17.5% concentration \n" ); document.write( "

Algebra.Com's Answer #72266 by ptaylor(2198) $\"\"$ $\"About$

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Let x=amount of pure Super Grow that needs to be added\r
\n" ); document.write( "\n" ); document.write( "Then 32-x=amount of 12% solution\r
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\n" ); document.write( "\n" ); document.write( "Now we know that the amount of pure Super Grow in the 12% solution (0.12(32-x))plus the amount of pure Super Grow added (x) has to equal the amount of pure Super Grow in the final mixture (0.175(32)). So our equation to solve is:\r
\n" ); document.write( "\n" ); document.write( "0.12(32-x)+x=0.175*32 get rid of parens \r
\n" ); document.write( "\n" ); document.write( "3.84-0.12x+x=5.6 subtract 3.84 from both sides\r
\n" ); document.write( "\n" ); document.write( "3.84-3.84-0.12x+x=5.6-3.84 collect like terms\r
\n" ); document.write( "\n" ); document.write( "0.88x=1.76 divide both sides by 0.88\r
\n" ); document.write( "\n" ); document.write( "x=2oz----------------amount of pure Super Grow that needs to be added\r
\n" ); document.write( "\n" ); document.write( "CK\r
\n" ); document.write( "\n" ); document.write( "0.12*30+2=0.175*32\r
\n" ); document.write( "\n" ); document.write( "3.6+2=5.6
\n" ); document.write( "5.6=5.6\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( "

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