document.write( "Question 1107576: Find an equation for the tangent line to the following curve,\r
\n" ); document.write( "\n" ); document.write( "h(x) = 19x − 5 ln x \r
\n" ); document.write( "\n" ); document.write( "at the point where x = e.
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Algebra.Com's Answer #722599 by Alan3354(69443)\"\" \"About 
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Find an equation for the tangent line to the following curve,\r
\n" ); document.write( "\n" ); document.write( "h(x) = 19x - 5ln(x) \r
\n" ); document.write( "\n" ); document.write( "at the point where x = e.
\n" ); document.write( "--------------
\n" ); document.write( "h(x) = 19x - 5ln(x)
\n" ); document.write( "h'(x) = 19 - 5/x
\n" ); document.write( "h'(e) = 19 - 5/e = slope of the tangent line.
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\n" ); document.write( "h(e) = 19e - 5
\n" ); document.write( "tangent point = (e,19e-5)
\n" ); document.write( "=============
\n" ); document.write( "y-y1 = m*(x-x1)
\n" ); document.write( "y-19e+5 = (19-5/e)*(x-e) = 19x - 19e - 5x/e + 5
\n" ); document.write( "y = 19x - 5x/e = x*(19 - 5/e)
\n" ); document.write( "
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