document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1107478>Question 1107478</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a) The ratio of similitude of two similar triangles is 3:4. If the perimeter of the larger triangle is 84m, what is the perimeter of the smaler triangle?\r<BR>\n" );
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document.write( "b)The lengths of the corresponding sides of two similar triangles are 32cm and 160 cm. If the area of the larger triangle is 160 cm sq., what is the area of the smaller triangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #722530 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=722530\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> perimeter will remain in the 3:4 ratio, so the perimeter of 84 for larger, 3:4=x:84<BR>\n" );
document.write( "x=63m for smaller\r<BR>\n" );
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document.write( "For a triangle, the area is (1/2)bh<BR>\n" );
document.write( "both b and h will each be (1/5) of the larger triangle<BR>\n" );
document.write( "Their product is (1/25), so the area will be 1/25 of the area or 160/25 or 6.4 cm^2.<BR>\n" );
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