document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=99295>Question 99295</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Perimeter\r<BR>\n" );
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document.write( "The perimeter is 34.  The width is 7 cm less than the length.  Figure length and width.\r<BR>\n" );
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document.write( "I did: \r<BR>\n" );
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document.write( "34=2w-7+2w </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #72252 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=72252\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> you're slightly off track ... the width is LESS than the length so the 7 is added to the width \r<BR>\n" );
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document.write( "34=2(w+7)+2w ... 34=2w+14+2w ... 20=4w ... 5=w ... so 12=L </SPAN>\n" );
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