document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1107454>Question 1107454</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is one more than four times another. If their sum is decreased by three, the result is thirteen. Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #722457 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=722457\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> one number: x<BR>\n" );
document.write( "other number: y<BR>\n" );
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document.write( "x = 4y + 1 I'll use this value for x below.<BR>\n" );
document.write( "x + y - 3 = 13<BR>\n" );
document.write( "4y + 1 + y - 3 = 13<BR>\n" );
document.write( "5y - 2 = 13<BR>\n" );
document.write( "5y = 15<BR>\n" );
document.write( "y = 3<BR>\n" );
document.write( "and x:<BR>\n" );
document.write( "x = 4y + 1; x = 4(3) = 1; x = 12 + 1 = 13<BR>\n" );
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document.write( "Check: \"If their sum is decreased by three, the result is thirteen\"<BR>\n" );
document.write( "3 + 13 - 3 = 13 Correct </SPAN>\n" );
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