document.write( "Question 1107393: To create a chocolate blend, chocolate in two concentrations, 71% cocoa and 44% cocoa, are combined together. If 12 ounces of the 71% chocolate is used, how many ounces of the 44% chocolate must be used to obtain a 56% chocolate blend? \n" ); document.write( "
Algebra.Com's Answer #722420 by greenestamps(13203)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "(1) The traditional algebraic solution method.... \n" ); document.write( "\"12 ounces of 71%, plus x ounces of 44%, equals (12+x) ounces of 56%\" \n" ); document.write( " \n" ); document.write( "I'll let you solve the equation to find the answer.... \n" ); document.write( "(2) By the method of alligation.... \n" ); document.write( "Once you understand it, this method gets you to the answer much faster and with less work. \n" ); document.write( " \n" ); document.write( "As shown in this diagram... \n" ); document.write( "the numbers in the first column are the percentages of the two ingredients (71%, 44%); \n" ); document.write( "the number in the middle column is the percentage of the mixture (56%); and \n" ); document.write( "the numbers in the third column are the differences, calculated diagonally, between the numbers in the first and second columns (71-56 = 15; 56-44 = 12). \n" ); document.write( "When the calculations are performed this way, the two numbers in the third column show the ratio in which the two ingredients must be mixed. \n" ); document.write( "So this diagram shows that the two ingredients must be mixed in the ratio 12:15; and since there are 12 ounces of the 71% chocolate, you need 15 ounces of the 44% chocolate. \n" ); document.write( " |