document.write( "Question 14373: log (1 + cos x + i sin x)/(cos x – 1 – i sin x) \n" ); document.write( "
Algebra.Com's Answer #7224 by khwang(438)\"\" \"About 
You can put this solution on YOUR website!
log \"+%281+%2B+cos+x+%2B+i%2A+sin+x%29%2F%28cos+x+-+1+-+i%2A+sin+x%29++\"\r
\n" ); document.write( "\n" ); document.write( " Multiplying the complex conjugate of the denominator.\r
\n" ); document.write( "\n" ); document.write( " Since z = \"+%281+%2B+cos+x+%2B+i%2A+sin+x%29%2F%28cos+x+-+1+-+i%2A+sin+x%29++\"
\n" ); document.write( " =
\n" ); document.write( " =
\n" ); document.write( " =
\n" ); document.write( " = \"+%28sin+x+%28-+sin+x+%2B+i+cos+x+%29%29%2F+++%28cos+x+%28cos+x+-+1%29+%29+\"\r
\n" ); document.write( "\n" ); document.write( " = \"sin+x%2F%28cos+x+%28cos+x+-+1%29+%29+\" \"%28-+sin+x+%2B+i+cos+x%29+\"
\n" ); document.write( " = \"+sin+x%2F%28cos+x+%281-cos+x%29+%29+\" \"%28+sin+x+-+i+cos+x+%29+\"
\n" ); document.write( " = \"sin+x%2F%28cos+x+%281-cos+x+%29+%29\" \"+%28cos%28x-+pi%2F2%29+%2B+i+sin+%28x-pi%2F2%29%29+\"
\n" ); document.write( " (polar coordinates) ...(***)\r
\n" ); document.write( "\n" ); document.write( " The definition of log z for complex number may be beyond your level.\r
\n" ); document.write( "\n" ); document.write( " Anyway,I give it here.
\n" ); document.write( " If the polar form for z = r \"e%5E%28i%2Atheta%29+\", \r
\n" ); document.write( "\n" ); document.write( " Here, by (***) the given z =
\n" ); document.write( "(where the radius r = |sin x/(cos x (1-cos x ) )|,
\n" ); document.write( " the argument \"theta+=+x-pi%2F2+\")\r
\n" ); document.write( "\n" ); document.write( "Hence, the natural logarithm ln(z).
\n" ); document.write( " ln(z) = ln(r) + i * theta = ln|sin x| - ln|cosx (1-cos x) + i \"%28x-pi%2F2%29\"
\n" ); document.write( " ... Answer
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\n" ); document.write( " This is a very boring question about calculations, try your best to understand the details.\r
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\n" ); document.write( "\n" ); document.write( " Kenny
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