document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1107287>Question 1107287</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is two less than a second number. Six times the first is 44 more than 4 times the second. Find the numbers.<BR>\n" );
document.write( "The value of the first number is <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #722309 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=722309\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  One number is two less than a second number.<BR>\n" );
document.write( "x = y - 2<BR>\n" );
document.write( " Six times the first is 44 more than 4 times the second.<BR>\n" );
document.write( "6x = 4y + 44<BR>\n" );
document.write( "simplify, divide by 2<BR>\n" );
document.write( "3x = 2y + 22<BR>\n" );
document.write( "replace x with (y-2)<BR>\n" );
document.write( "3(y-2) = 2y + 22<BR>\n" );
document.write( "3y - 6 = 2y + 22<BR>\n" );
document.write( "3y - 2y = 22 + 6<BR>\n" );
document.write( "y = 28 is the second number<BR>\n" );
document.write( "and<BR>\n" );
document.write( "x = 28 - 2<BR>\n" );
document.write( "x = 26 is the first number<BR>\n" );
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