document.write( "Question 1107302: The circle with equation
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document.write( "x²+y²-4x-6y+9=0 touches the y-axis.
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document.write( "Find
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document.write( "(a) the coordinates of the point of contact.
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document.write( "(b) the length of the tangent to the circle from the origin. \n" );
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Algebra.Com's Answer #722306 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! rewrite as x^2-4x+y^2-6y=-9 \n" ); document.write( "complete the square for x and y \n" ); document.write( "x^2-4x+4+y^2-6y+9=-9+13 \n" ); document.write( "(x-2)^2+(y-3)^2=4 \n" ); document.write( "This is a circle with center (2, 3) and radius 2 \n" ); document.write( "It touches the y-axis where x=0 \n" ); document.write( "Therefore, (-2)^2+(y-3)^2=4 \n" ); document.write( "(y-3)^2=0 \n" ); document.write( "y=3, so it touches at (0,3) and is a \"bounce,\" 3 units from the origin. \n" ); document.write( " |