document.write( "Question 1107302: The circle with equation
\n" ); document.write( "x²+y²-4x-6y+9=0 touches the y-axis.
\n" ); document.write( "Find
\n" ); document.write( "(a) the coordinates of the point of contact.
\n" ); document.write( "(b) the length of the tangent to the circle from the origin.
\n" ); document.write( "

Algebra.Com's Answer #722306 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
rewrite as x^2-4x+y^2-6y=-9
\n" ); document.write( "complete the square for x and y
\n" ); document.write( "x^2-4x+4+y^2-6y+9=-9+13
\n" ); document.write( "(x-2)^2+(y-3)^2=4
\n" ); document.write( "This is a circle with center (2, 3) and radius 2
\n" ); document.write( "It touches the y-axis where x=0
\n" ); document.write( "Therefore, (-2)^2+(y-3)^2=4
\n" ); document.write( "(y-3)^2=0
\n" ); document.write( "y=3, so it touches at (0,3) and is a \"bounce,\" 3 units from the origin.
\n" ); document.write( "
\n" ); document.write( "
\n" );