document.write( "Question 1107244: a 2 digit number gives a remainder of 6 when divided by 10. it gives a remainder of 5 when divided by 7. find the greatest possible 2 digit number \n" ); document.write( "

Algebra.Com's Answer #722256 by ikleyn(52811) $\"\"$ $\"About$

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\n" ); document.write( "96.\r
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document.write( "    Obviously, this 2-digit number is of the form N =x6, where x is the \"tens\" digit and 6 is the \"ones\" digit.\r\n" );
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document.write( "    Since \"it gives a remainder of 5 when divided by 7\", it means that  N-5 is divisible by 7.\r\n" );
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document.write( "    N-5 is the number of the form  x1  (referring to N = x6), i.e. N-5 is ended by \"1\".\r\n" );
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document.write( "    Among 2-digit numbers there are only TWO of the form x1 that are divisible by &. They are 21 and 91.\r\n" );
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document.write( "    91 is the largest, and it produces  N = 96.\r\n" );
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