document.write( "Question 1107081: One solution contains 2 parts salt to 8 parts water, and another contains 3 parts salt to 5 parts water. How much of each should be mixed together in order to obtain 280 quarts of a solution that is 3 parts salt to 7 parts water?\r
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document.write( "ANSWER: __ quarts and ____ quarts respectively\r
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document.write( "Thanks for helping! <3 \n" );
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Algebra.Com's Answer #722239 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! let's convert these solutions to percent salt \n" ); document.write( ": \n" ); document.write( "One solution contains 2 parts salt to 8 parts water, and \n" ); document.write( "solution a: 2/10 = .2 solution is 20% salt \n" ); document.write( ": \n" ); document.write( " another contains 3 parts salt to 5 parts water. \n" ); document.write( "solution b: 3/8 = .375 solution is 37.5% salt \n" ); document.write( ": \n" ); document.write( " How much of each should be mixed together in order to obtain 280 quarts of a solution that is 3 parts salt to 7 parts water? \n" ); document.write( "3/10 = .30 resulting solution is 30% salt \n" ); document.write( ": \n" ); document.write( "A mixture equation in decimal form \n" ); document.write( ".2a + .375b = .30(280) \n" ); document.write( "a + b = 280 \n" ); document.write( "a = 280 - b \n" ); document.write( "In the 1st equation replace a with (280-b) \n" ); document.write( ".2(280-b) + .375b = .30(280) \n" ); document.write( "56 - .2b + .375b = 84 \n" ); document.write( ".175b = 84 - 56 \n" ); document.write( ".175b = 28 \n" ); document.write( "b = \n" ); document.write( "b = 160 qts of 37.5% solution (3:5 \n" ); document.write( "then \n" ); document.write( "280 - 160 = 120 qts of the 20% solution (2:8) \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check: \n" ); document.write( ".2(120) + .375(160) = .3(280) \n" ); document.write( "24 + 60 = 84\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |