document.write( "Question 1107207: if \"f%28x-2%29=x%5E3%2B3x%5E2-3x%2B7\",find \"f%281%29\" \n" ); document.write( "
Algebra.Com's Answer #722220 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
f(x-2)=x^3+3x^2-3x+7,find f(1)
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\n" ); document.write( "If x-2 = 1, x = 3
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\n" ); document.write( "f(1) = f(3-2) = 3^3+3*3^2-3*3+7 = 27+27-9+7 = 52
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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