document.write( "Question 1107203: The general term of Un of a series is defined by the relation Un+1=0.3*(1+Un). n is greater than or equal to 1 and U1 =1. Calculate U2, U3 and U4.
\n" ); document.write( "A second series is defined with the general term Vn, by the relation Vn=Un - 0.5 n is greater than or equal to 1.
\n" ); document.write( "Show that this series(Vn) is an exponential series.
\n" ); document.write( "Express Vn and hence Un as function of n. \n" ); document.write( "
Algebra.Com's Answer #722214 by stanbon(75887)\"\" \"About 
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The general term of Un of a series is defined by the relation Un+1=0.3*(1+Un). n is greater than or equal to 1 and U1 =1.
\n" ); document.write( "Calculate
\n" ); document.write( "U2 = 0.3(1+1) = 0.6
\n" ); document.write( "U3 = 0.3(1.6) = 0.48
\n" ); document.write( "U4 = 0.3(1.48 = 0.444
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\n" ); document.write( "A second series is defined with the general term Vn, by the relation Vn=Un - 0.5 n is greater than or equal to 1.
\n" ); document.write( "Show that this series(Vn) is an exponential series.
\n" ); document.write( "V1 = U(1)-0.5
\n" ); document.write( "V2 = [U(1)-0.5]2 = 2U(1)-1
\n" ); document.write( "V3 = [2U(1)-1]3 = 6U(1)-3
\n" ); document.write( "I see no exponentiation.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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\n" ); document.write( "\n" ); document.write( "Express Vn and hence Un as function of n. \n" ); document.write( "
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