document.write( "Question 1107201: If the geometric mean of 0.25 or 1 over 4, and 4 is x+3, find the possible values of x. \n" ); document.write( "
Algebra.Com's Answer #722209 by ikleyn(52790)\"\" \"About 
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document.write( "The geometric mean of 0.25 and 4 is \"sqrt%280.25%2A4%29\" = \"sqrt%281%29\" = 1.\r\n" );
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document.write( "We are given that 1 = x+3.  Hence,  x = 1 - 3 = -2.\r\n" );
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