document.write( "Question 1107093: One pair of integers (x.y) solves \"+sqrt%28+4%2Asqrt%28+7+%29%2B11+%29=y%2Bsqrt%28+x+%29+\", find x*y. \n" ); document.write( "
Algebra.Com's Answer #722096 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "\"+sqrt%28+4%2Asqrt%28+7+%29%2B11+%29=y%2Bsqrt%28+x+%29+\"\r\n" );
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document.write( "square both sides:\r\n" );
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document.write( "\"+4%2Asqrt%28+7+%29%2B11+=%28y%2Bsqrt%28+x+%29%29%5E2+\"\r\n" );
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document.write( "\"+4%2Asqrt%28+7+%29%2B11+=y%5E2%2B2y%2Asqrt%28+x+%29%2Bx+\"\r\n" );
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document.write( "Since x and y are integers we can set the integer terms\r\n" );
document.write( "on the left equal to the integer terms on the right\r\n" );
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document.write( "\"11+=y%5E2%2Bx+\"\r\n" );
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document.write( "and we can set the irrational terms on the left equal to the\r\n" );
document.write( "irrational terms n the right:\r\n" );
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document.write( "\"+4%2Asqrt%28+7+%29+=2y%2Asqrt%28+x+%29+\"\r\n" );
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document.write( "It's quite obvious that to have integer solutions\r\n" );
document.write( "x must be 7, and y must be 2.\r\n" );
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document.write( "We see if that checks in\r\n" );
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document.write( "\"11+=y%5E2%2Bx+\"\r\n" );
document.write( "\"11+=2%5E2%2B7+\"\r\n" );
document.write( "\"11+=4%2B7+\"\r\n" );
document.write( "\"11+=11+\"\r\n" );
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document.write( "Yes it does, so x*y = 7*2 = 14\r\n" );
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document.write( "Edwin
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